undefined method `name' for "41":String

rubyonrails-talk
#1

plz see this
http://pastie.org/878267
reply if u find any error or suggestion…
plz its urgent

Regards,
Shyam
+91-9716-18-9650

#2

plz see this
http://pastie.org/878267
reply if u find any error or suggestion…
plz its urgent

Regards,
Shyam
+91-9716-18-9650

Shyam, local variables are not accessing within the view. Thus, you’ll need to change

charges = Charge.find(:all,:conditions =>"company_id =#{comp_id}")

to

@charges = Charge.find(:all,:conditions => [ "company_id = ?" , comp_id ] )

Next, I would recommend reading "Agile Web Development with Rails 3rd" as well

as the [guides.rubyonrails.org](http://guides.rubyonrails.org).

Good luck,

-Conrad
#3 
Conrad

Hi Thanks for replying
but problem was some thing else…
thanks

Regards,
Shyam
+91-9716-18-9650

#4

You have
<td><%=h charge.name %></td>

Where is the variable called charge setup?

You might like to have a look at rails guide on debugging, it will
show you several ways of analysing this sort of issue when you cannot
see the problem by code inspection. http://guides.rubyonrails.org/
Look particularly at the use of ruby-debug.

Colin

#5 
Conrad

Hi Thanks for replying
but problem was some thing else…
thanks

Regards,
Shyam
+91-9716-18-9650

Did you resolve the issue?

-Conrad

#6

I think in the cherry-picking of code to put into pastie, an "each"
line was missed out around here:
  <% charges = params[:charges]
  if charges %>
    <td><%=h charge.name %></td>

But the upshot is; if you are populating "charges" from the params
hash, what is in params? I'd put money on params[:charges] returning
an array of integers that are ids of charges (hence getting "undefined
method `name' for "41":String" as the error). If you want "charges" to
be a collection of Charge objects that match the ids in
params[:charges] - get that all sorted in the controller.