Cayce Balara wrote:
Using an "in" clause should accomplish the same thing: Contact_List.find(:all, :select => 'DISTINCT contact_id', :conditions => ['list_id in ?', "('" + params[:joblist][:list_id].join("','") + "')"])
Also no testing, but I believe Rails will do the joining for you (which is partly why his original attempt resulted in the way it did). So the above code can be simplified to:
Contact_List.find :all, :select => 'DISTINCT contact_id', :conditions => ['list_id IN (?)', params[:joblist][:list_id]]
Eric