Hi, I need a concise regexp pattern to validate a complete http URL. Can someone help me in this? Thanks,
Well, I don’t know if “concise” is the right word, but a regexp in http://www.ietf.org/rfc/rfc2396.txt (page 29) will help you:
The following line is the regular expression for breaking-down a URI
reference into its components.
^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))? 12 3 4 5 6 7 8 9
The numbers in the second line above are only to assist readability;
they indicate the reference points for each subexpression (i.e., each
paired parenthesis). We refer to the value matched for subexpression
as $. For example, matching the above expression to
[http://www.ics.uci.edu/pub/ietf/uri/#Related](http://www.ics.uci.edu/pub/ietf/uri/#Related)
results in the following subexpression matches:
$1 = http: $2 = http $3 = //[www.ics.uci.edu](http://www.ics.uci.edu) $4 = [www.ics.uci.edu](http://www.ics.uci.edu) $5 = /pub/ietf/uri/ $6 = <undefined> $7 = <undefined> $8 = #Related $9 = Related
where indicates that the component is not present, as is
the case for the query component in the above example. Therefore, we
can determine the value of the four components and fragment as
scheme = $2 authority = $4 path = $5 query = $7 fragment = $9
and, going in the opposite direction, we can recreate a URI reference
from its components using the algorithm in step 7 of Section 5.2.
Rob Biedenharn http://agileconsultingllc.com
+1 513-295-4739
Skype: rob.biedenharn
Here is my way to handle URL (in the file)
Attachments: http://www.ruby-forum.com/attachment/6443/url_pattern.rb