RoR-3.0.1
I have this case statement:
case n.hll_normalize when "common name" @my_correspondent.correspondent_common_name = s when "legal name" . . . else raise ArgumentError, "#{n} attribute is not provided for." end
hll_normalize is defined as:
def hll_normalise strip.squeeze(" ").mb_chars.downcase end
I pass this case statement this value for n: "common name"
When run with Ruby-1.8.7p302 this works. The exact same code run with Ruby-1.9.2p0 yields:
common name attribute is not provided for. (ArgumentError)
When I enter rails console then I see this:
$ rails c Loading development environment (Rails 3.0.1) ruby-1.9.2-p0 > x = "common name" => "common name" ruby-1.9.2-p0 > x.mb_chars => common name ruby-1.9.2-p0 > x.mb_chars.downcase => common name ruby-1.9.2-p0 > "common name" == x.mb_chars.downcase => true ruby-1.9.2-p0 > "common name" == x.strip.squeeze(" ").mb_chars.downcase => true ruby-1.9.2-p0 > case x.strip.squeeze(" ").mb_chars.downcase ruby-1.9.2-p0 ?> when "uncommon" then puts "nothing" ruby-1.9.2-p0 ?> when "common name" then puts x ruby-1.9.2-p0 ?> end => nil ruby-1.9.2-p0 >
So, what is the case statement sensitive wrt mb_chars that changes the result of "common name" == x.strip.squeeze(" ").mb_chars.downcase when used as an argument? Is there a nil coming back from somewhere in the case statement argument evaluation when mb_chars is involved?
This is definitely related to mb_chars because this works:
ruby-1.9.2-p0 > case x.strip.squeeze(" ").downcase ruby-1.9.2-p0 ?> when "uncommon" then puts "nothing" ruby-1.9.2-p0 ?> when "common name" then puts x ruby-1.9.2-p0 ?> end common name => nil ruby-1.9.2-p0 >