file upload error(can't convert Tempfile into String)

rubyonrails-talk
1

i tried a method to implementa file uploader by using amethod below

this is ma controlller method to upload

def save_imports     Contactslist.save(params[:list])     render :text => "File uploaded successfully"

this is ma view file

.remote   - form_for(@list, :url=> save_imports_list_path(@list, :format => "js"), :html => { :multipart => true, :target => "uploading", :onsubmit => "$('list_submit).disabled = true" }) do |f|     = link_to_close edit_list_path(@list)     .section       %small         #{t :add_contacts_from_file}       %table{ :width => 500, :cellpadding => 0, :cellspacing => 0 }         %tr           %td{ :valign => :top }           .label.top.req #{t :upload_new}:           =f.file_field :uploads, :style => "width:240px"

    .buttonbar       = f.submit "#{t:save_contacts}", :onclick => "this.disabled = true"       #{t :or}       = link_to_cancel edit_list_path(@list)

i created amodel contact list and nclude amethod as given below

class Contactslist < ActiveRecord::Base def self.save(upload)     name = upload['uploads']     puts name     directory = "public/avatars"     # create the file path     path = File.join(directory, name)     # write the file     File.open(path, "wb") { |f| f.write(upload['uploads'].read) }   end end when i tried to upload a file its showing errors as

TypeError in ListsController#save_imports

can't convert Tempfile into String

can anyone help.is there any fault in this method?actually i wanted toupload this files into a table callled contactslists or to move to a folder in my application pls provide help

2

Hey Tony,

You just need

name = upload[‘uploads’].original_filename

instead of

name = upload[‘uploads’]

/Lasse

3

Lasse Bunk wrote:

Hey Tony,

You just need

  name = upload['uploads'].original_filename

instead of

  name = upload['uploads']

/Lasse

thanks a lot its working now