I am confused on the second call :-
class Foo def <<(param) "hi" end end foo = Foo.new foo.<<(1) # => "hi"
foo << 1 # => "hi" # I didn't use `.` method,then how method `<<` has been called?
I am confused on the second call :-
class Foo def <<(param) "hi" end end foo = Foo.new foo.<<(1) # => "hi"
foo << 1 # => "hi" # I didn't use `.` method,then how method `<<` has been called?
Love U Ruby wrote in post #1120864:
I am confused on the second call :-
class Foo def <<(param) "hi" end end foo = Foo.new foo.<<(1) # => "hi"
foo << 1 # => "hi" # I didn't use `.` method,then how method `<<` has been called?
I would image that it works the same as it does for the +, -, *, and / methods.
Example: $ irb irb(main):001:0> 5 + 7 => 12 irb(main):002:0> 5.+(7) => 12