Confusion with method call without `.` operator

rubyonrails-talk
1

I am confused on the second call :-

class Foo   def <<(param)     "hi"   end end foo = Foo.new foo.<<(1) # => "hi"

foo << 1 # => "hi" # I didn't use `.` method,then how method `<<` has been called?

2

Love U Ruby wrote in post #1120864:

I am confused on the second call :-

class Foo   def <<(param)     "hi"   end end foo = Foo.new foo.<<(1) # => "hi"

foo << 1 # => "hi" # I didn't use `.` method,then how method `<<` has been called?

I would image that it works the same as it does for the +, -, *, and / methods.

Example: $ irb irb(main):001:0> 5 + 7 => 12 irb(main):002:0> 5.+(7) => 12