Saving a new object n times to the DB

rubyonrails-talk
1

Hello,

I have a generate method that generate PIN codes and serial numbers n times, n comes from a user-submitted form, something like that:

<% form_for :card, :url => {:action => “generate”} do |f| -%>

Number of cards
<%= f.text_field :number_of_cards, :size => 10 %>

<%= submit_tag ‘Generate’ %> <% end -%>

In the controller I have:

def generate

params[:number_of_cards].to_i.times do pin = rand(999999999999).to_s.center(12, rand(9).to_s) serial = rand(999999999999).to_s.center(12, rand(9).to_s) Card.create({:pin => pin, :serial => serial})

end end

Everything looks OK, but when I put a number and submit the form I got nothing! No error messages and no records are saved to the database !!! When I for example put : 3.times do … etc

3 new records are successfully created in the database !

what’s the problem? Maybe params[:number_of_cards] doesn’t get the value from the form? Why? And if so why don’t I get error about some nil value?

Your help is really appreciated.

Regards

2

Because the parameter is being submitted as params[:card][:number_of_cards] (that's what form_for does). You can see this in your logs. You get no error because nil.to_i is 0

Fred

3

You have form_for :card and then f.text_field :number_of_cards, so you’ll get a params[:card][:number_of_cards]

Your params[:number_of_cards] is therefore almost certainly nil and nil.to_i == 0

It can help tremendously to put:

<%= debug(params) %>

Into the view that comes back so you can see what really happens (or just go look in the log/development.log where you should also see the params hash).

-Rob

Rob Biedenharn http://agileconsultingllc.com

Rob@AgileConsultingLLC.com

4

Thanks Frederick and Rob, now it works :slight_smile: This debug option is really useful I didn’t know about it before>

Thanks