Print Layout

rubyonrails-talk
1

Hello All,

We have developed the following code in application.rb

  def determine_layout     if !params[:layout].blank? and params[:layout] == "print"       @layout = "print"     else       @layout = "public"       @layout = "admin" if params[:controller] =~ /admin/     end     return @layout   end

This code allows us to use link with param in URL "layout=print", so the user can preview any page in browser without the menu, header, footer and etc,

in this project we have only 2 layouts, but there are project where we have 30 - 40 layouts, does anybody know how to write this function in best way like

  def determine_layout     if !params[:layout].blank? and params[:layout] == "print"       @layout = "print"     else          *** by default in controllers ***     end     return @layout   end

Regards, Pavel

2

Hi Pavel,

se_pavel wrote:

This code allows us to use link with param in URL "layout=print", so the user can preview any page in browser without the menu, header, footer and etc,

The easiest way of doing this is with CSS. You have a separate stylesheet for print media with the items you don't want displayed set to 'display: none;'.

HTH, Bill